Question

expand (x-4) ³ of the following​

Answer 1

Answer:

x^3+-12 x^2+48 x-64

Step-by-step explanation:

(x-4)^3 = sum_(k=0)^3 binomial(3, k) x^(3-k)×(-4)^k = binomial(3, 0) x^3 (-4)^0+binomial(3, 1) x^2 (-4)^1+binomial(3, 2) x^1 (-4)^2+binomial(3, 3) x^0 (-4)^3:

binomial(3, 0) x^3-4 binomial(3, 1) x^2+16 binomial(3, 2) x-64 binomial(3, 3)

binomial(3, 0) = 1, binomial(3, 1) = 3, binomial(3, 2) = 3 and binomial(3, 3) = 1:

x^3-3 4 x^2+3 (-4)^2 x+(-4)^3

(-4)^2 = 16:

x^3-4 3 x^2+16 3 x+(-4)^3

(-4)^3 = (-1)^3×4^3 = -4^3:

x^3-4 3 x^2+16 3 x+-4^3

4^3 = 4×4^2:

x^3-4 3 x^2+16 3 x-4×4^2

4^2 = 16:

x^3-4 3 x^2+16 3 x-16 4

4×16 = 64:

x^3-4 3 x^2+16 3 x-64

16×3 = 48:

x^3-4 3 x^2+48 x-64

-4×3 = -12:

Answer 2

Answer:

(x)3+64+(12)x2+48

Step-by-step explanation:

(x+4)3 = (x)3+(4)3+3×(x)×(4)×(x+4)

=(x)3 +(64) + (12x)×(x+4)

=(x)3+64+(12)x2+48

I hope it will be helpful