Question

Expand x minus 2 by 3 y whole cube

Answer 1

Answer:

3×*3-8/27y*3

Step-by-step explanation:

.........…

Answer 2

The expansion is $(x-\frac{2}{3})^3=x^3-2x^2+\frac{2}{3}x-\frac{8}{27}$

Step-by-step explanation:

Given : Expression $(x-\frac{2}{3})^3$

To find :

Using algebraic identity,

$(a-b)^3=a^3-b^3-3a^2b+3ab^2$

Here, $a=x$ and $b=\frac{2}{3}$

Substitute the value,

$(x-\frac{2}{3})^3=x^3-(\frac{2}{3})^3-3(x)^2(\frac{2}{3})+3x(\frac{2}{3})^2$

$(x-\frac{2}{3})^3=x^3-\frac{8}{27}-2x^2+\frac{2}{3}x$

$(x-\frac{2}{3})^3=x^3-2x^2+\frac{2}{3}x-\frac{8}{27}$

Therefore, the expansion is $(x-\frac{2}{3})^3=x^3-2x^2+\frac{2}{3}x-\frac{8}{27}$

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