Question

Expand (x + y - z ) square

Answer 1

Proof: Let x + y = k then, (x + y + z)2 = (k + z)2 = k2 + 2kz + z2 (Using identity I) = (x + y)2 + 2( x + y)z + z2 = x2 + 2xy + y2 + 2 xz + 2yz + z2 = x2 + y2 + z2 + 2xy + 2yz + 2zx ...
i hope it is a good answer pls mark as brainliest

Answer 2

Hey friend,
Here is the answer you were looking for:

${(x + y - z)}^{2} \\ \\ using \: the \: formula \\ {(a + b - c)}^{2} = {(a)}^{2} + {(b)}^{2} + {(c)}^{2} + 2ab - 2bc - 2ca \\ \\ = {(x)}^{2} + {(y)}^{2} + {(z)}^{2} + 2xy - 2yz - 2zx \\ \\ = {x}^{2} + {y}^{2} + {z}^{2} + 2xy - 2yz - 2xz$
Hope this helps!!!

@Mahak24

Thanks...
☺