Question

Expand (Z^2-2z+5)/((z-2)(Z^2+1)) ;1<(abs(Z))<2 by Laurent series

Answer 1

Answer:

If R > 0 then the series converges absolutely to an analytic function for |z − z0| < R. 2. The series diverges z1(z2 + z3) = (x1 + iy1)(x2 + y2 + i(x3 + y3)). = x1(x2 + ... of p(z). Thus h(z)=(z − 1 − i)(z − 1+ i) = z2 − 2z + 2 divides p(z) ... )2 . Expanding the right hand side of this inequality we have.Let f(z)=1(z−1)(z−2) and let R1={z|1<|z|<2} and R2={z||z|>2}. How do you find the Laurent series convergent on R1? Also how do you do it for ...