Question

expanded : [ 3/2 x + 1] cube
​

Answer 1

27/8x^3+7x^2+9/2x+1

Step-by-step explanation:

[3/2x+1]^3 can be written as

(3x+2)^3*1/8

we know that,

(a+b)^3= a^3+b^3+3ab(a+b)

=> [3x+2]^3= 27x^3+8+3×3x×2(3x+2)

=> 27x^3+8+54x^2+36x----- equation (1)

so the answer is 1/8 times equation 1

that is 27/8x^3+1+7x^2+9/2x

mark this as brainliest if correct