Question

expanded form of (2a+3b+4c)² is_______​

Answer 1

Answer:

We know,

(x+y+z)2=x2+y2+z2+2xy+2yz+2zx        [Identity]

Here, 

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒ (2a+3b+4c)2=(2a)2+(3b)2+(4c)2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

                                  =4a2+9b2+16c2+12ab+24bc+16ac

I think it would be brainleast solution thanks

Answer 2

Answer:

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

(2a + 3b + 4c)² =

(2a)² + (3b)² + (4c)² + 2(2a)(3b) + 2(3b)(4c) + 2(4c)(2a)

(2a + 3b + 4c)² =

4a² + 9b² + 16c² + 12ab + 24bc + 16ac