Question

expanded form of log [(x ^2 *y)/z]​

Answer 1

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2 log x + log y - log z

step-by-step explanation:

given,

log (${x}^{2}y/z$)

now,

we know that,

log(mn) = log m + log n

so,

usinf this formula,

we get,

= log ${x}^{2}$ + log( y/z)

now,

we know that,

log ${m}^{n}$ = n( log m)

so,

According to this,

we get,

= 2 log x + log (y/z)

now we know that,

log (m/n) = log m - log n

so according to this Formula,

we get,

= 2 log x + log y - log z