Expanding bracket102*103
Answers
Answered by
4
hey mate!!
here's ur answer:-)
![(102 \times 103) \\ (100 + 2)(100 + 3) \\ \\ using \: identity \: \\ (x + a)(x + b) = \\ x {}^{2} + (a + b)x + ab \\ \\ 100 {}^{2} + (2 + 3)100 + 2 \times 3 \\ 10000 + 500 + 6 \\ 10506 (102 \times 103) \\ (100 + 2)(100 + 3) \\ \\ using \: identity \: \\ (x + a)(x + b) = \\ x {}^{2} + (a + b)x + ab \\ \\ 100 {}^{2} + (2 + 3)100 + 2 \times 3 \\ 10000 + 500 + 6 \\ 10506](https://tex.z-dn.net/?f=%28102+%5Ctimes+103%29+%5C%5C+%28100+%2B+2%29%28100+%2B+3%29+%5C%5C++%5C%5C+using+%5C%3A+identity+%5C%3A+%5C%5C++%28x+%2B+a%29%28x+%2B+b%29++%3D++%5C%5C+x+%7B%7D%5E%7B2%7D++%2B+%28a+%2B+b%29x+%2B+ab+%5C%5C++%5C%5C+100+%7B%7D%5E%7B2%7D++%2B+%282+%2B+3%29100+%2B+2+%5Ctimes+3+%5C%5C+10000+%2B+500+%2B+6+%5C%5C+10506)
hope it helps
here's ur answer:-)
hope it helps
Arumugamsoundaryaa:
Thank you so much
Similar questions