Expanding form of (x+2)whole cube
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( x + 2 )³ = x³ + 2³ + 3x² × 2 + 3x × 2²
=>
( x + 2 )³ = x³ + 6x² + 12x + 8
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Answer: Using Identity, (a+b)³ = a³+b³+3ab(a+b)
→(x+2)³ = x³+(2)³+3(x)(2)(x+2)
→x³+8+6x(x+2)
→x³+8+6x²+12x
→x³+6x²+12x+8
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