expands using suitable identity (2x-y + 3)2
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Answer:
4x^2+ 4xy+ y^2+ 12x- 6y+ 9
Step-by-step explanation:
=(2x-y+ 3)^2
=((2x-y)^2 + 2(2x-y)3+ 3^2
=(4x^2+ 4xy+ y^2+ 12x- 6y+ 9)
=4x^2+ 4xy+ y^2+ 12x- 6y+ 9
Hope this is correct.
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