Question

expandthe following please fast
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Answer 1

Answer:

3a−4b−3c)²= 9a²+16b²+9c²-24ab+24bc−18ac

Step-by-step explanation:

(3a-4b-3c)²

By using identity (x+y+z)²= x²+y²+z²+2(xy+yz+zx)

Take x= 3a, y= −4b and z= −3c

(3a−4b−3c)²= (3a)²+(-4b)²+(-3c)²+2(3a×(-4b)+(-4b)×(-3c)+(-3c)×3a)

(3a−4b−3c)²= 9a²+16b²+9c²+2(-12ab+12bc−9ac)

(3a−4b−3c)²= 9a²+16b²+9c²-24ab+24bc−18ac