Math, asked by akshay8858, 1 year ago

expansion cube of (198)

Answers

Answered by 7771999511
45
(200-2)^3
(a-b)^3 =a^3-b^3-3ab (a-b)
(200-2)^3=200^3-2^3-3×200×2 (200-2)
=8000000-8-1200 (200-2)
=8000000-8-240000-2400
=7,762,392
Answered by jaya8765
0

Answer:

7,762,392

Step-by-step explanation:

the formula for cube expansion is :

(a-b)³= (a-b)(a-b)²

(a-b)³=(a-b)(a²+b²-2ab)

(a-b)³=(a³-b³-3a²b+3ab²)

(a-b)³=a³-b³-3ab(a-b)

let a=204 b=6 ; a-b=198

(204-6)³= 204³-6³-((3(204)(6)(204-6))

(204-6)³=7,762,392

therefore the expansion cube of (198) is 7,762,392

for more examples of expansion of numbers visit the link below :

https://brainly.in/question/4232407

https://brainly.in/question/1405660

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