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Expansion of (1 + x)" in ascending powers of x is
(A) 1-nx +
n(n 1) x2_n(n − 1) (n 2)
2!
3!
X3 +.
(B) 1-nx + ( x nn +
x2_n(n + 1) (n + 2)
n(n+1)
(C) 1 + nx +
x2 + n(n + 1) (n +2)
n(n-1
(D) 1 + nx +
271) x2 + n(n − 1)(n-2)
3!
X3 +.
x +
3!
x +
3!
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Answer:
in ascending powers of x is
(A) 1-nx +
n(n 1) x2_n(n − 1) (n 2)
2!
3!
X3 +.
(B) 1-nx + ( x nn +
x2_n(n + 1) (n + 2)
n(n+1)
(C) 1 + nx +
x2 + n(n + 1) (n +2)
n(n-1
(D) 1 + nx +
271) x2 + n(n − 1)(n-2)
3!
X3 +.
x +
3!
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