Math, asked by shree9676, 2 months ago

...
Expansion of (1 + x)" in ascending powers of x is
(A) 1-nx +
n(n 1) x2_n(n − 1) (n 2)
2!
3!
X3 +.
(B) 1-nx + ( x nn +
x2_n(n + 1) (n + 2)
n(n+1)
(C) 1 + nx +
x2 + n(n + 1) (n +2)
n(n-1
(D) 1 + nx +
271) x2 + n(n − 1)(n-2)
3!
X3 +.
x +
3!
x +
3!

Answers

Answered by araj3024
0

Answer:

in ascending powers of x is

(A) 1-nx +

n(n 1) x2_n(n − 1) (n 2)

2!

3!

X3 +.

(B) 1-nx + ( x nn +

x2_n(n + 1) (n + 2)

n(n+1)

(C) 1 + nx +

x2 + n(n + 1) (n +2)

n(n-1

(D) 1 + nx +

271) x2 + n(n − 1)(n-2)

3!

X3 +.

x +

3!

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