Expansion of (a-b-c)² = ?
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Answered by
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(a - b - c )^2
= ( a - b - c ) ( a - b - c )
= a ( a - b - c ) - b ( a - b - c ) - c ( a - b - c )
= a ^2 - ab - ac - ab + b ^2 + bc - ac + bc + c 2
= a ^2 + b ^2 + c ^2 - 2ab + 2bc - 2ac
Thetefore,
( a - b - c )^2 = a^2 + b ^2 + c ^2 - 2ab + 2bc - 2ac
I hope this will useful to you.
*****
= ( a - b - c ) ( a - b - c )
= a ( a - b - c ) - b ( a - b - c ) - c ( a - b - c )
= a ^2 - ab - ac - ab + b ^2 + bc - ac + bc + c 2
= a ^2 + b ^2 + c ^2 - 2ab + 2bc - 2ac
Thetefore,
( a - b - c )^2 = a^2 + b ^2 + c ^2 - 2ab + 2bc - 2ac
I hope this will useful to you.
*****
Answered by
2
hi there is ur answer :)
(a-b-c)^2=
(a-b-c)^2=
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