Question

Expansion of a perfect gas into vacuum is related with
(1) ∆H = 0
(2) q = 0
(3) W = 0
(4) All of these​

Answer 1

When an Ideal gas is expanded into vacuum, it does no work. (W =0) Hence, no change in the internal energy and thus in the temperature of the gas. This means the q = 0, change in internal energy and enthalpy are also zero. Hence, Option (4) is correct.

Answer 2

Answer:

the answer is all of these

Explanation:

If an ideal gas or perfect gas

expands into vacuum, it does

no work

i.e, work done = 0

& this process is considered to

be an adiabatic process,

where q=0

ΔU=0

Also, ΔH=ΔU+Workdone

ΔH=0+0

ΔH=0