Math, asked by molletibavita0, 1 month ago

EXPANSION OF Sin 5A IN TERMS OF SINE

Answers

Answered by ItzurAdi

4

Sin5A=sin(3A+2A)

= sin3A*cos2A+cos3A*sin2A

= (3sinA-4sin^3 A) *(cos^2 A-sin^2 A) +

(4cos^3A-3cosA)*(2sinA*cosA)

#ItzurAdi✨

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