Question

expansion of (x-1/x)² is​

Answer 1

$</p><p>{(a - b)^2 = a^2 + b^2 - 2ab}$

$(x - \frac{1}{x} ) {}^{2} = \\ \: {x}^{2} + \: \frac{1}{ {x}^{2} } \: - 2 \times x \times \frac{1}{x}$

${x}^{2} + \frac{1}{x} - 2$

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