Math, asked by SanjanaKarmakar, 1 month ago

Expansion:
(x+2/x-3)(x-2/x-3)​

Answers

Answered by JeetChowdhury
0

Answer:

(X+2/x-3) (x-2/x-3)

x^2-4/x^2-6x+9

x^2+2x-2x-4/x^2-3x-3x+9

X(X+2)-2(X+2)/X(x-3)-3(x-3)

(X+2)(x-2)/(x-3)(x-3)

X=+_2/3

Answered by reliance25
0

Hey friend, this is the answer -

(x+2/x-3)(x-2/x-3)​

= (x + 2)(x - 2) / (x - 3)(x - 3)

= x^2 - 2^2 / (x - 3)^2              [∵ (a+b)(a-b) = a^2-b^2]

= x^2 - 4 / x^2 + 3^2 + 2(x)(3) [∵ (a-b)^2 = a^2+b^2-2ab]

= x^2 - 4 / x^2 + 9 + 6x

Hope it will help

PLease mark my answer as brainliest

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