Expansions.
Two positive numbers x and y are such that x>y. If the difference of these nunbers is 5 and their product is 24,find :
(i) Sum of these numbers.
(ii) difference of their cubes.
(iii) sum of their cubes.
sol...
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x-y= 5
xy= 24
x = 5+y
So in above eqn,we get,
y^2+5y-24=0
So y= 5 , -3
-3 is neglected
Hence x is 5
Sum of these nos= 11
Difference of their cubes = 512 - 27 = 485
Sum of their cubes = 512 + 27 = 539
xy= 24
x = 5+y
So in above eqn,we get,
y^2+5y-24=0
So y= 5 , -3
-3 is neglected
Hence x is 5
Sum of these nos= 11
Difference of their cubes = 512 - 27 = 485
Sum of their cubes = 512 + 27 = 539
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