Expectation value of two spin 1/2 particles where particle 1 along z axis and particle 2 along another axis?
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So I got to thinking that Sn2=ℏ2cosθ(100−1)Sn2=ℏ2cosθ(100−1) making the argument that the z-component of particle 2 is projected onto n^n^. It gave the right answer for the expectation value ⟨Sz1Sn^2⟩⟨Sz1Sn^2⟩ but I am thinking it has to be wrong. That a measurement along n^n^must also return the same eigenvalues as Sz1Sz1, namely ±ℏ2±ℏ2 thus Sz1=Sn2Sz1=Sn2. Is this correct
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for a two spin 1/2 particles, the expectation value of ⟨Sz1Sn2⟩⟨Sz1Sn2⟩ is −ℏ24cosθ−ℏ24cosθ when the system is prepared to be in the singlet state |00⟩=12√(|↑⟩|↓⟩−|↓⟩|↑⟩)|00⟩=12(|↑⟩|↓⟩−|↓⟩|↑⟩).
It is given that the matrix Sz1Sz1 returns particle 1's z component. Where
Sz1=ℏ2(100−1)
Sz1=ℏ2(100−1)
Now for particle 2 the matrix Sn2Sn2 gives the component of spin angular momentum along an axis denoted by the unit vector n^n^. where θθ is the angle between the z-axis and n^n^.
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HERE'S THE ANSWER ✌
_________________
⬇⬇⬇⬇
for a two spin 1/2 particles, the expectation value of ⟨Sz1Sn2⟩⟨Sz1Sn2⟩ is −ℏ24cosθ−ℏ24cosθ when the system is prepared to be in the singlet state |00⟩=12√(|↑⟩|↓⟩−|↓⟩|↑⟩)|00⟩=12(|↑⟩|↓⟩−|↓⟩|↑⟩).
It is given that the matrix Sz1Sz1 returns particle 1's z component. Where
Sz1=ℏ2(100−1)
Sz1=ℏ2(100−1)
Now for particle 2 the matrix Sn2Sn2 gives the component of spin angular momentum along an axis denoted by the unit vector n^n^. where θθ is the angle between the z-axis and n^n^.
✅✅✅✅✅✅✅✅
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