Question

Expects 0.64 in the form of
af by where p and q are
intergers and q is not
0​

Answer 1

Answer:

Let x = 0.6 recurring

Then, x = 0.666..... ....(i)

implies 10x = 6.666........ .....(ii)

Substracting (i) from (ii),we get

9x = 6 implies x = 6/9

implies x = 2/3

Answer 2

Answer:

let x =0.064bar equation1 multiply 10 on both sides 10x = 0.064bar-10 10x = 0.64bar equation2 multiply 10 again on both sides 10.10x=0.64bar•10 100x=6.4 equation3 subtract equation 2 from3 100x-10x=6.4bar-0.64 90x=5 x=5/9 ans hope this is heipful if it is incorrect please correct me