Question

Expend the following using identity
1.(x-2y+3z²)²​

Answer 1

Step-by-step explanation:

Answer:

(x-2y-3z)²

(x-2y-3z)²=x²+4y²+9z²-4xy+12yz-6zx

Step-by-step explanation:

/* We know the algebraic identity:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca */

Here ,

(x-2y-3z)²

= [x²+(-2y)+(-3z)]²

= x²+(-2y)²+(-3z)²+2×x(-2y)+2×(-2y)(-3z)+2×(-3z)x

= x²+4y²+9z²-4xy+12yz-6zx

Therefore,

(x-2y-3z)²

=x²+4y²+9z²-4xy+12yz-6zx

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Answer 2

Answer:

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(x-2y-3z)²

=[(x)-(2y+3z)]²

=x²-2x(2y+3z)+(2y+3z)²

=x²-4xy-6xz+4y²+2.2y.3z+9z²

=x²+4y²+9z²-4xy-6xz+12yz

Step-by-step explanation:

hope it would be helpful for u