Question

Experiment to prepare m20 solution of oxalic acid

Answer 1

Answer:

Explanation:

preparation of standard solution of oxalic acid [ 250ml / M/20 ] 

we know, molar mass of oxalic acid ,  = 126g/mol 

given, molarity = 0.05M

and volume of solution , V = 250ml

so, mass of oxalic acid = M × molarity × V/1000

= 126 × 0.05 × 250/1000 

= 126 × 0.05/4 

= 1.575 g 

now, determination of strength of  using standard solution of oxalic acid. 

in this titration, potassium permanganate is titrant while oxalic acid is analyte. also we observed that potassium permanganate is oxidising agent. and oxalic acid is reducing agent.The reaction between potassium permanganate and oxalic acid is carried out in an acidic medium because permanganate ion in the acidic medium is a very strong oxidizing agent. Acidity is introduced by adding dilute sulphuric acid.

The chemical reaction that takes place during titration can be represented by the chemical equation.

molecular reaction, 

--------------------------------------------------------

is overall reaction. 

ionic reaction, 

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overall ionic redox reaction. 

from balance chemical equation, it is clear that two mole of potassium permanganate reacts with five moles of oxalic acid.