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From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.
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Answered by
27
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Here is the solution:
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Find the distance between the building and the tower:
tan θ = opp/adj
tan (45) = 7/distance
1 = 7/distance
distance = 7 m
Find the height from the the building to the top of the tower:
tan θ = opp/adj
tan (60) = height/7
height = 7 tan(60)
height = 7√3 m
Find the height of the tower:
Height = 7 + 7√3
Height = 7 ( 1 + √3)
Height = 19 m (nearest m)
Answer: The height of the tower is 19 m
how ?
it would be 7 not 70
Hmm. it's wrongly mentioned
yes
corrected.
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Answered by
26
refer to the above solution
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No clear ans
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Similar questions
Now, In triangle ABC, tan 45 = 1 = AB/BC
So, AB = AE = 7 m
Again in triangle AED,
tan 60 = root 3 = DE/AE
So, DE= AE.root3 = 7 . root3 m
Height of the cable tower = h + 7 = 7 root 3 m+ 7 m = 7 (1+ root3) m