Question

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Q: The reading of a spring balance when a block is suspended from it in air is 60 N. The reading is changed to 40 N when the block is submerged in water. The relative density of the block is_______ .

Answer 1

20N=vdg
V=2×10-3cm3
60N=d12×10-3×10
d=3×10-3kgdm-3

Answer 2

The relative density of the block is 3.

Explanation:

The weight of any object depends on the gravitational pull it is experiencing and the medium it is placed in.

The wait that is placed here in air is 60 Newton the gravitational pull acting on that object in air is 60 Newtons.

Now when the weight is kept in water there will be a certain loss of weight due to the density of water hence it becomes 40 Newtons.

We need to find out the relative density of the mass or block in different mediums and this is given by specific gravity which is a quotient of of weight in air and loss of weight in water which gives,

= $\frac{60}{(60-40)}$

⇒ 3.

To Know more:

A wooden block floats in a glycerine in such a way that its 2/5th volume remains above surface.If relative density of wood is 0.78 ,calculate the relative density of glycerine

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