Experts, kindly help me with this question
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Explanation:
(a) As OP < OQ, A lives closer to the school than B.
(b) For x = 0, t = 0 for A; while t has some finite value for B. Therefore, A starts from the school earlier than B.
(c) Since the velocity is equal to slope of x-t graph in case of uniform motion and slope of x-t graph forB is greater that that for A =, hence B walks faster than A.
(d) It is clear from the given graph that both A and B reach their respective homes at the same time.
(e) B moves later than A and his/her speed is greater than that of A. From the graph, it is clear that B overtakes A only once on the road.
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