Physics, asked by pratimav31pbep1c, 1 year ago

experts please answer this question ​

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Answered by amitraja26
1
[V]. = [at]

LT^-1 = A T

A = LT^-2


[V] = [ BT^2]


B = V / T^2

B = LT^-1 X T^-2

B = LT^-3

K = [V] [T^2]

K = LT^-1 X T^2

K= LT^1


pratimav31pbep1c: thanks
Answered by gomathi02
1

Explanation:

the dimension of velocity is m/s^1

v=At+Bt^2+k/t^2

therefore.

v=At=Bt^2=k/t^2

m/s^1=As therefore A=m/s^2

A=[LT^-2]

m/s^1=Bt^2=Bs^2

B=[LT^-3]

as like k=[LT^3]


gomathi02: sorry the k=[LT^1]
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