experts please answer this question
Attachments:
Answers
Answered by
1
[V]. = [at]
LT^-1 = A T
A = LT^-2
[V] = [ BT^2]
B = V / T^2
B = LT^-1 X T^-2
B = LT^-3
K = [V] [T^2]
K = LT^-1 X T^2
K= LT^1
LT^-1 = A T
A = LT^-2
[V] = [ BT^2]
B = V / T^2
B = LT^-1 X T^-2
B = LT^-3
K = [V] [T^2]
K = LT^-1 X T^2
K= LT^1
pratimav31pbep1c:
thanks
Answered by
1
Explanation:
the dimension of velocity is m/s^1
v=At+Bt^2+k/t^2
therefore.
v=At=Bt^2=k/t^2
m/s^1=As therefore A=m/s^2
A=[LT^-2]
m/s^1=Bt^2=Bs^2
B=[LT^-3]
as like k=[LT^3]
Similar questions