Experts, please help:
How can 4^ n be represented as 2^2n?
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Answered by
4
as 4^n
(2^2)^n
I hope it is helpful for u
(2^2)^n
I hope it is helpful for u
Answered by
3
4ⁿ
= (4)ⁿ
= (2x2)ⁿ
= (2²)ⁿ
= 2²ⁿ
since (mª)ⁿ = mªⁿ
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= (4)ⁿ
= (2x2)ⁿ
= (2²)ⁿ
= 2²ⁿ
since (mª)ⁿ = mªⁿ
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bhatiaaditi13:
Thanks SARDARshubham
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