Question

Expess the relationship berween rate of formation of water and rate of disappearance of oxygen in following reaction:
2H2 + O2 gives rise to 2H2O

Answer 1

Rate of formation of H2O = 1/2 x d[H2O]/dt
rate of disappearance of O2  = -d[O2]/dt

now, 1/2 x d[H20]/dt   =  - d[O2]/dt

d[H2O]/dt  = -2 x d[O2]/dt 

hence , rate of formation of H2O  is twice the
 rate of disappearance of  O2

hope , it helps