expinential function whose graph of 3/2, 27
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Step-by-step explanation:
for the given points x: 3/2 . y: 27
y = ab^x
27 = ab^3/2
27/ b^3/2 = a
27×2/b^3 = a
54/b^3 =a
18 b^ = a
so 27 = 18 b^3/2
54 = 18 b^
54/18 = b^
3 = b^ so
if b should be greater than o it should be exponential function.
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