Question

explain ( 1) n + 1 rule (2) hand rule of maximum multiplicity (3) why2 D and 3
F orbital are not possible​

Answer 1

Answer:

Because those angular momenta are too high for the given quantum levels.

Recall that the first two quantum numbers are:

n=1,2,3,...

l=0,1,2,...,n−1 ↔ s,p,d,f,g,h,i,k,...

where n is the principal quantum number indicating the energy level, and l is the angular momentum quantum number indicating the shape of the orbital.

Since l can be no greater than n−1 (i.e. lmax=n−1), it follows that the maximum l for each energy level is:

n=1⇒lmax=0⇒s

n=2⇒lmax=1⇒p

n=3⇒lmax=2⇒d

n=4⇒lmax=3⇒f

⋮ ⋮

As a result, the highest angular momentum orbitals we have are 1s, 2p, 3d, 4f, etc. We cannot have 1p, 2d, 3f, 4g, etc.

so moyler diagram is given