Question

explain 100 gram of water = hydrogen 11 and oxygen 89 mathematically

Answer 1

Answer:

2H2O -> O2 + 2H2

Or… 1 mol of water produces 1 mol of hydrogen and 1/2 mol of oxygen

each mol of water is 18.016 g per mol

100 g = 100/18.016 or 5.55062 moles of water

Each mol of hydrogen is 2.016 g

so it requires 2.016*100/18.016 or 11.19 g of hydrogen

oxygen required is 0.5*100/18.016 moles or 2.77531 moles

molar mass of oxygen is 32 g

so 2.7753 x 32 mol = 88.81 g of oxygen

together 88.81 g oxygen and 11.19 g hydrogen gets you back to 100 g of water

I think it would be brainleast answer thanks

Answer 2

Answer:

100000000000000000000000000000000

Explanation: