explain 12th one it's diagram is in front of 11nth question
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In rectangle ABCD; diagonals are AC and BD.
AC and BD intersect at O.
So, angles AOB and COD are opposite angles.
So, angle AOB = angle COD = 62°.
Also, we know that diagonals of rectangle are equal in length and they bisect one another.
So, AC = BD and OC = OD.
So, triangle OCD is an isosceles triangle with OC = OD. Which means, angle OCD = angle ODC.
In triangle OCD, sum of three angles is 180°.
Angle ODC = (180° - 62°) / 2 = 59°.
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