explain 4th and 6th question
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4. cot theta = 3/4
cot theta = b/p
b = 3k
p = 4k
h = 5k (by PGT)
cosec theta = h/p
cosec theta = 5/4
6. 3 sec theta = 5
sec theta = 5/3
sec theta = h/b
h = 5k
b = 3k
p = 4k(by PGT)
cos theta = 1/sec
cos theta = 3/5
sin theta = p/h
sin theta = 4/5
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