Explain a passenger bus is accelerated uniform from 18Km h–¹ to 54Km h–¹ in 5s.Calculate
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you can simply apply the first equation of motion i.e.,
v=u+at
putting the values...
15=5+a×5
15-5=5a
10=5a
a=10/5 =2
acceleration is 2 m/s^-2...
hope it will help
v=u+at
putting the values...
15=5+a×5
15-5=5a
10=5a
a=10/5 =2
acceleration is 2 m/s^-2...
hope it will help
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