Math, asked by yogavamsi1999, 7 months ago

explain about derivative of 3xe^3xcosx..please fast is urgent. please. Don't spam. ​

Answers

Answered by nehav6085
0

Step-by-step explanation:

The log of a product is the sum of the logs, so ln6x = ln6+lnx. The derivative of a sum is the sum of the derivatives. But since ln6 is a constant and the derivative of a constant is zero then d(ln(6x))/dx = d(ln6)/dx + d(lnx)/dx = 0+1/x = 1/x.

Answered by abdulhasib6559
0

Answer:

xkvzkxhvglggxoxggfxoupfupfgzxoygxfpu

Step-by-step explanation:

please sorry you check the link

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