explain about derivative of 3xe^3xcosx..please fast is urgent. please. Don't spam.
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Step-by-step explanation:
The log of a product is the sum of the logs, so ln6x = ln6+lnx. The derivative of a sum is the sum of the derivatives. But since ln6 is a constant and the derivative of a constant is zero then d(ln(6x))/dx = d(ln6)/dx + d(lnx)/dx = 0+1/x = 1/x.
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Answer:
xkvzkxhvglggxoxggfxoupfupfgzxoygxfpu
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