explain about Hoffman elimination reaction and where it is used.
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Answer:
The Hofmann elimination is an organic reaction used to convert an amine with a β-hydrogen to an alkene using methyl iodide, silver oxide and water under thermal conditions. The mechanism begins with an attack of the amine on methyl iodide to form an ammonium iodide salt.
Hofmann elimination, also known as exhaustive methylation.
In this reaction, least stable alkene is formed, i.e., the one with least number of Alpha hydrogen. A process where a tertiary amine reacts to create a quaternary ammonium and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat. When a quarternary ammonium hydroxide is decomposed on heating then the hydrogen is preferentially eliminated from that beta carbon which is joined to largest number of hydrogen atoms.