explain acceleration due to newton's law of gravity
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Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s2. It has both magnitude and direction, hence, it's a vector quantity. Acceleration due to gravity is represented by g. The standard value of g on the surface of the earth at sea level is 9.8 m/s2.
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Answer:
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.Under the action of gravitational force, the body begins to accelerate toward the earth’s centre which is at a distance ‘r’ from the test mass.
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.Under the action of gravitational force, the body begins to accelerate toward the earth’s centre which is at a distance ‘r’ from the test mass.Then, ma = GMm/r2 (Applying principle of equivalence)
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.Under the action of gravitational force, the body begins to accelerate toward the earth’s centre which is at a distance ‘r’ from the test mass.Then, ma = GMm/r2 (Applying principle of equivalence)⇒ a = GM/r2 . . . . . . . (1)
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.Under the action of gravitational force, the body begins to accelerate toward the earth’s centre which is at a distance ‘r’ from the test mass.Then, ma = GMm/r2 (Applying principle of equivalence)⇒ a = GM/r2 . . . . . . . (1)The above acceleration is due to the gravitational pull of earth so we call it acceleration due to gravity, it does not depend upon the test mass. Its value near the surface of the earth is 9.8 ms-2.
velocity of an object changes only under the action of a force, in this case, the force is provided by the gravity.Under the action of gravitational force, the body begins to accelerate toward the earth’s centre which is at a distance ‘r’ from the test mass.Then, ma = GMm/r2 (Applying principle of equivalence)⇒ a = GM/r2 . . . . . . . (1)The above acceleration is due to the gravitational pull of earth so we call it acceleration due to gravity, it does not depend upon the test mass. Its value near the surface of the earth is 9.8 ms-2.Therefore, the acceleration due to gravity (g) is given by = GM/r2.