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Step-by-step explanation:
Proof =
DP=CQ
then, DP+PQ=CQ+PQ
DQ=CP
AQ=BP
AD perpendicular to CD and BC is also perpendicular to CD
so, we can say that angle ADQ=90°= angle BCP
So, we have
angle ADQ=angle BCP (A)
AQ=BQ (S)
DQ =CP(S)
By SAS property angle DAQ= angle CBP
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