Question

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Answer 1

hey buddy here is your answer

Qns(1)==>given perimeter of rhombus is 28

==> side of rhombus = 28/4= 7 cm ( all sides are equal in rhombus)

now given area of rhombus = 98 cm^2

==> so we know the formula = A = S*H(altitude)

==> 98 = 7*H

==>98/7= h

==> 14 = h
so we got altitude of rhombus is 14 cm

Qns (2)

==>radius of wire = 42

==>length of wire = 2πr

==>2*22/7*42= 264 cm

==> let common ratio of rectangle is X

==>perimeter of rectangle = 2(l*b)

==> 2(6x+5x)= 22 x cm

==> 22x = 264

==> X= 264/22 = 12

==> now we know that 5 is smaller than 6 So smaller side

==> 5*12= 60 cm

Qns (3)

given condition = circumference of circle and area of circle is equal

==> so we know circumference of circle = 2πr

==> area of circle is = πr^2

==> according to condition

==>2πr = πr^2

==> 2=πr^2/ πr
==> 2 = r

so as we know diameter is 2*r

2*2= 4 cm diameter (answer)

Qns(4)

Area of lawn = 5/16 hectare

==>1 hectare = 10000 sqm

==> 10000*5/16= 3125 sqm

==> let common ratio of base and hight is X

==>1x*5x=3125

==>5x^2 = 3125

==>x^2 = 3125/5= 625

==> X= √625 = 25

put X value in ratio

1*x= 25 base
5*x(25)= 125 m

hope it helps