explain any one reducing property of so2 by giving chemical equation
Answers
Answered by
12
Explanation:
Featuring sulfur in the +4 oxidation state, sulfur dioxide is a reducing agent. It is oxidized by halogens to give the sulfuryl halides, such as sulfuryl chloride: SO2 + Cl2 → SO2Cl. ... SO2 + 2 H2S → 3 S + 2 H2O.
Answered by
0
The reducing nature of sulfur dioxide is due to the development of nascent hydrogen.
Explanation:
- Oxygen in nature appears when it reacts with strong oxygen agents.
- Sulfur dioxide reducing agent because sulfur has d orbit so it easily extends its oxidation state from +4 to +6 and thus acts as a reducing agent.
- Sulfur dioxide is the oxidizing agent of the claustrophobic process, which is widely used in oil refineries.
- In the case of sulfur, due to the presence of empty d-orbital, it can extend its oxidation state to +4 to +6 oxidation state.
- Therefore, it acts as a reducing agent.
- dissolves in water to form sulfuric acid which is why it has an acidic character.
Similar questions
Math,
5 months ago
Math,
5 months ago
Hindi,
5 months ago
English,
10 months ago
India Languages,
10 months ago