Chemistry, asked by rajgupta71355, 10 months ago

explain any one reducing property of so2 by giving chemical equation ​

Answers

Answered by TheDreamCatcher
12

Explanation:

Featuring sulfur in the +4 oxidation state, sulfur dioxide is a reducing agent. It is oxidized by halogens to give the sulfuryl halides, such as sulfuryl chloride: SO2 + Cl2 → SO2Cl. ... SO2 + 2 H2S → 3 S + 2 H2O.

Answered by anjalin
0

The reducing nature of sulfur dioxide is due to the development of nascent hydrogen.

Explanation:

  • Oxygen in nature appears when it reacts with strong oxygen agents.
  • Sulfur dioxide reducing agent because sulfur has d orbit so it easily extends its oxidation state from +4 to +6 and thus acts as a reducing agent.
  • Sulfur dioxide is the oxidizing agent of the claustrophobic process, which is widely used in oil refineries.
  • In the case of sulfur, due to the presence of empty d-orbital, it can extend its oxidation state to +4 to +6 oxidation state.
  • Therefore, it acts as a reducing agent.
  • SO_{2} dissolves in water to form sulfuric acid which is why it has an acidic character.
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