Explain any two methods to two insert a table in a presentation. Q2. How will you display two application windows side by side ?
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Rhyming scheme is the pattern of rhymes at the end of each line of a poem or song. It is usually referred to by using letters to indicate which lines rhyme; lines designated with the same letter all rhyme with each other.
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Since, each student requires 9m2 of floor and given the no. of students is 50.
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18m
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h ⇒5400=450Xh
Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h ⇒5400=450Xh ⇒h=5400/450= 12m
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