Computer Science, asked by pareeknaman41, 5 hours ago

Explain any two methods to two insert a table in a presentation. Q2. How will you display two application windows side by side ?
Question Of Information Technology​

Answers

Answered by pcplionelmessi
0

Answer:

Rhyming scheme is the pattern of rhymes at the end of each line of a poem or song. It is usually referred to by using letters to indicate which lines rhyme; lines designated with the same letter all rhyme with each other.

Answered by deepak9140
2

Explanation:

Since, each student requires 9m2 of floor and given the no. of students is 50.

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18m

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h                      ⇒5400=450Xh

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h                      ⇒5400=450Xh                      ⇒h=5400/450=  12m

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