English, asked by spharsh32, 6 months ago

Explain: Be has higher ∆iH1 than B.​

Answers

Answered by bedikajoshi90
32

Answer:

▪︎Since 2s-electrons are more strongly attracted by the nucleus than 2p-electrons, therefore, lesser amount of energy is required to knock out a 2p-electron than a 2s-electron. Consequently, ∆iH of Be is higher than that ∆iH of B.

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