Question

explain Biot Savart law derive expression for the magnetic field at the centre of a current carrying circular loop​

Answer 1

Answer:

Using Biot-Savart's law, derive an expression for magnetic field at any point on axial line of a current carrying circular loop. Hence, find magnitude of magnetic field intensity at the centre of circular coil. ... And it is inversely proportional tot hr square of the distance between the point and the element.

Answer 2

Biot Savart Law

Explanation:

• The Biot-Savart Law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points
• To derive this law, we first take this equation for the electric field. This is the full version, where we use muu-zero over 4pi instead of the electrostatic constant k. Since we're looking at a wire, we replace the charge q with I dl, which is the current in the wire, multiplied by a length element in the wire. Basically, it's treating this little chunk of the wire as our charge. And we also replace the electric field E with a magnetic field element dB because a moving charge produces a magnetic field, not an electric field
• Last of all, we have to realize that a current has a direction (unlike a charge). So we need to make sure the direction of the current affects our result. We do that by adding sine of the angle between the current and the radius. That way, if the wire is curvy, we'll take that into account
• Expression for magnetic field= d→B = μ04π i d→s ×^rr2