Explain brown ring test with the help of chemical equation
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A nitrate test, known as the brown ring test can be performed by adding iron(II) sulfate to the solution, then slowly adding concentrated sulfuric acid and watching for a brown ring on the test tube, which will indicate the presence of the nitrate ion.
The overall reaction is the reduction of the nitrate ion by iron(II) which is oxidised to iron(III) and formation of a nitrosonium complex where nitric oxide is reduced to NO−
2HNO3+ 3H2SO4 + 6FeSO4 --->> 3Fe2(SO4)3+ 2NO + 4H2O(Remaining)[Fe(H2O)6]SO4 + NO = [Fe(H2O)5(NO)]SO4+ H2O
This test is sensitive up to 2.5 micrograms and a concentration of 1 in 25,000 parts.
The overall reaction is the reduction of the nitrate ion by iron(II) which is oxidised to iron(III) and formation of a nitrosonium complex where nitric oxide is reduced to NO−
2HNO3+ 3H2SO4 + 6FeSO4 --->> 3Fe2(SO4)3+ 2NO + 4H2O(Remaining)[Fe(H2O)6]SO4 + NO = [Fe(H2O)5(NO)]SO4+ H2O
This test is sensitive up to 2.5 micrograms and a concentration of 1 in 25,000 parts.
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a solution of ferrous sulphate is taken and then h2so4 is added slowly and heated it will appear afterwards that a brown ring will be formed at the junction of two liquid which will fade it solution is slightly moved this is so because sulphuric acid being heavier settles down and ferrous sulphate floats on it and no2 is evolved which gives this colour
hope helps
a solution of ferrous sulphate is taken and then h2so4 is added slowly and heated it will appear afterwards that a brown ring will be formed at the junction of two liquid which will fade it solution is slightly moved this is so because sulphuric acid being heavier settles down and ferrous sulphate floats on it and no2 is evolved which gives this colour
hope helps
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