Explain by giving step by step explanation of this question
Attachments:
Answers
Answered by
2
Sorry brother , I was busy..
So , I said..the question will be solved by AP formula..
Circumference of circle= 2π r
therefore, circumference of semicirlce= πr
Circumference of circle with radius 1cm = π *1
Circumference of circle with radius 2 cm = π * 2
......
circumference of circle with radius 27 cm = π * 27
So the series is[ π *1 + π * 2... π *27]
taking pie common ..
π[1+2+3+4.....27]... equation 1
NOW , first term of AP is 1 and common difference is 1
SUM OF N TERMS IS GIVEN BY FORMULA ...
SN = N/2 *[2*a + (N -1)*d]
Sum of 27 terms .. = 27/2*[2*1+(27-1)*1]
= 27/2 *28
= 27*14
And putting sum of 27 terms in eq. 1... π(sum of 27 terms )
therefore , 22/7 * 27*14
= 22*2*27
Answer is 1188
Hope it helps you all❤❤❤
So , I said..the question will be solved by AP formula..
Circumference of circle= 2π r
therefore, circumference of semicirlce= πr
Circumference of circle with radius 1cm = π *1
Circumference of circle with radius 2 cm = π * 2
......
circumference of circle with radius 27 cm = π * 27
So the series is[ π *1 + π * 2... π *27]
taking pie common ..
π[1+2+3+4.....27]... equation 1
NOW , first term of AP is 1 and common difference is 1
SUM OF N TERMS IS GIVEN BY FORMULA ...
SN = N/2 *[2*a + (N -1)*d]
Sum of 27 terms .. = 27/2*[2*1+(27-1)*1]
= 27/2 *28
= 27*14
And putting sum of 27 terms in eq. 1... π(sum of 27 terms )
therefore , 22/7 * 27*14
= 22*2*27
Answer is 1188
Hope it helps you all❤❤❤
Answered by
2
a=1 , d=1
sn= n
Similar questions