Question

explain by step by step
if I fell it is correct
then I mark your list as brainlist

Answer 1

HEY MATE!

HERE'S YOUR ANSWER

1)Let 2nd term be x.

So AP is

2, x,26

Since it is an AP,

common difference is same

therefore,

Second term-first term=third term-second term...

x-2 = 26-x

x+x = 2+26

2x = 28

x =28/2

x =14

So, 2, 14, 26

2)we know that second term =13 (a2)

a2=a+(2-1)d

13=a+1×d

13=a+d

13-d=a (part 1 to find the 1st

a=13-d term)

a =13-d

(part 2 to find the 4th term)(a4)

a4=a+(4-1)d

3=a+3×d

3=a+3d

3-3d=a

a=3-3d

FROM PART 1 AND 2,

13-d=3-3d

13-3=d-3d

10= -2d

10/-2=d

-5=d

d=-5

PUTTING VALUES OF (d )IN PART 1

a=13-d

=13-(-5)

=13+5

=18

NOW WE HAVE TO FIND (a)

a2=a+(n-1)d

=18+(3-1)×(-5)

=18+2×(-5)

=18-10

=8

SO a2=8

18, 13, 8, 3

3)Given a=5 (1st term)

a4=9/1/2=19/2

a4=a+(4-1)d

19/2=5 +3d

19/2 -5=3d

19-2×5/2 =3d

9/2 =3d

9/2 ×1/3 =d

3/2=d

d=3 /2

a2 (2nd term )

a2=a+(2-1)d

=a+1d

=5+3/2

=5 (2)+3/2=13/2

a3 (third term)

a3=a+(3-1)d

=a+2d

=5+2 (3/2)

=5+3=8

HENCE,

a2=13/2=6/1/2

a3=8

5, 6/1/2, 8, 9/1/2