Geography, asked by puvvalalakshmidurga, 4 hours ago

explain current division rule for a two branches parallel resistive network

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Answered by dapushree

7

Answer:

IT = IR1 + IR2. As the two resistors are connected in parallel, for Kirchhoff's Current Law, (KCL) to hold true it must therefore follow that the current flowing through resistor R1 will be equal to: IR1 = IT – IR2. and the current flowing through resistor R2 will be equal to: IR2 = IT – IR1.

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