Question

Explain degenerate case of the parabola with the help of a diagram.​

Answer 1

Answer:

The degenerate form of a parabola is a line or two parallel lines. For this conic section, the coefficients \begin{align*}A=B=C=0\end{align*} in the general equation. Thus, the resulting general equation is \begin{align*}Dx+Ey+F=0\end{align*}. The degenerate form of a hyperbola is two intersecting lines

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Answer 2

Answer:

Answer

Number of atoms in close packaging = 0.5 mol

1 has 6.022×10

23

particles

So that

Number of close-packed particles

=0.5×6.022×10

23

=3.011×10

23

Number of tetrahedral voids = 2 × number of atoms in close packaging

Plug the values we get

Number of tetrahedral voids =2×3.011×10

23

=6.022×10

23

Number of octahedral voids = number of atoms in close packaging

So that

Number of octahedral voids =3.011×10

23

Total number of voids = Tetrahedral void + octahedral void

=6.022×10

23

+3.011×10

23

=9.03×10

23

Explanation:

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