Math, asked by keerthanavadranapu, 8 months ago

Explain derivations of trignometry?

Answers

Answered by harini1608

1

Step-by-step explanation:

Derivatives of Basic Trigonometric Functions

We have already derived the derivatives of sine and cosine on the Definition of the Derivative page. They are as follows: (sinx)′=cosx,(cosx)′=−sinx. ... (cotx)′=(1tanx)′=−1tan2x⋅(tanx)′=−1sin2xcos2x⋅1cos2x=−cos2x sin2x⋅cos2x =−1sin2x.

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